In actual boiler operation, there are many uncontrollable factors that affect the consumption of fuel. However, according to a formula, we can simply calculate the fuel consumption of the boiler under ideal conditions, thus giving the customer some information as a reference. For example, a 1 ton SZL series boiler produced by ZBG has a biomass pellets(the GCV=18392 KJ/Nm3) consumption of 160 kg/h.
We need to know that the calculation of fuel consumption has a close relationship with these factors, the boiler efficiency, the calorific value of the fuel, and the capacity of the boiler.
Fuel consumption = Heat Input required (kcal/hr.) / Calorific Value of that fuel (kcal/kg)
Heat Input required (kcal/hr.)= (Boiler Capacity x (Steam Enthalpy - Feed water Enthalpy)) / (Boiler Efficiency)
I will give you an example, so you can take this as reference and calculate fuel required for any capacity of Boiler for any fuel. It is known that the capacity of a biomass boiler is 2 ton. From the boiler parameter information, we can know That steam pressure of the boiler is 10.5 kg/cm2 (g), the steam temperature is 185.5 Deg c (Saturated Steam), boiler efficiency is 89%, and the enthalpy of saturated steam is 664.2 kcal/kg, enthalpy of feed water The biomass fuel is wood, the calorific value (GCV) is 2272 kcal/kg(It is the amount of heat liberated in Kcal by the complete combustion of 1 kg of Fuel).
We finally calculated that a fuel consumption of a 2 ton wood biomass boiler with an efficiency of 89% was 553 kg/hr.
Heat Input required = 2000 x (664.2 -105)/0.89 = 1256629.21 kcal/hr
Fuel consumption= 1256629.21/2272 = 553 kg/hr